Question

what is the no. of electron present in 18 ml of water. Please give step by step explanation. Don't post irrelevant answers​

Answer 1

The total number of electrons present in 18 ml of water is 6.023×10²⁴

DETAILED EXPLANATION:

Number of electron in one molecule of H₂O is 2+8=10.

Density =1 g/ml

∴ 18 ml means 18 g

Moles = $\frac{18}{18}$ = 1

Molecules =6.023×10²³

Electrons = 6.023 × 10²³ × 10 [this 10 = no. of e⁻ in one molecule of H₂O]

                = 6.023×10²⁴

OR IN WORDS....

water density is equal to 1

So 18 ml water= 18 gram water = one mole water

In one molecule of  water there are 10 electrons are present

Thus in one mole water there are 6.023×10²³ molecules of water are present

Thus number of electrons in one mole = 10×6.023×10²³ =6.023×10²⁴ electrons

Hope it Helps

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