what is the no. of gram atoms of Oxygen in 6.02×10^24 CO
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Therefore, there are 10 gram molecules of O in 6.022 × 10²⁴ molecules of CO. CO contains 1 atom of carbon and 1 atom of oxygen. So there are 6.02 * 10^24 oxygen atoms. No of gram moles = no of atoms /avogadros no which is 10.
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