Question

what is the no. of molecules present in 22.4dm³ of any gas at s.t.p??​

Answer 1

Answer:

There are 6.022*10^23 molecules present in 22400cm^3 gas.

Therefore the no. of molecules present in 22.4cm^3=

6.022*10^23 * 22.4cm^3 divide by:

224000 cm^3

Hence we get the ans as 6.022*10^20 molecules.