Question

what is the no. of moles of Fe(OH)3 that can be produced by allowing 1 mole of FeS3, 2 moles of H2O & 3 moles of O2 to react?​

Answer 1

What is the number of moles of Fe(OH

3

) that can be produced by allowing 1 mole of Fe

2

S

3

, 2 moles of H

2

O and 3 moles of O

2

to react? (as nearest integer)

2Fe

2

S

3

+6H

2

O+3O

2

→4Fe(OH)

3

+6S

MEDIUM

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ANSWER

2Fe

2

S

3

+6H

2

O+3O

2

→4FeOH

3

+6S

2 6 3 4 (From stoichiometry)

1 2 3 ? (Given)

So, H

2

O is limiting reagent here.

Fe(OH)

3

produces =4×

6

2

=1.34 moles

So, nearest integer is 1.

Answer 2

$\huge\boxed{\fcolorbox{red}{blue}{ QUESTION }}$

what is the no. of moles of Fe(OH)3 that can be produced by allowing 1 mole of FeS3, 2 moles of H2O & 3 moles of O2 to react?

$\orange{\underline{\textit{\green{\bf{CONCEPT \:used:-}}}}}$

IS OF LIMITING REAGENT :-

$\orange{\underline{\textit{\green{\bf{</strong><strong>DEFINITION</strong><strong>:</strong><strong>-</strong><strong> }}}}}$

The limiting reagent in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed. The amount of product formed is limited by this reagent, since the reaction cannot continue without it

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$\orange{\underline{\textit{\red{\bf{Equation \:used:-}}}}}$

2FeS3+6H2O+3O2---> 4 Fe(OH)3 +6S

$\orange{\underline{\textit{\blue{\bf{BUT GIVEN STOICHIOMETRY:-}}}}}$

1FeS3+2H2O+3O2---> xFe(OH)3 +yS

so limiting agent :- Is H2O

bez we require 3 mole of H2O to react with 1 Mole FeS3 but we r only having 2 moles of it .

so H2O limits the reaction :-

so acc to limiting agent product formed us equal to :-

6 moles of H2O react to form 4 moles of Fe(OH)3

so 1 mole react to form :-

$\frac{4}{6} moles \:$

so 2 moles react to form :-

$2 \times \frac{4}{6} = \frac{8}{6}$

which is equal to 1.333...

so nearest whole number --> one

so one mole of Fe(OH)3 FORMED

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