What is the no.of p electron in a neutral atom of an element has 2K,8L,11M and 2N electrons.
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The exact answer for this question is 23
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Explanation:
Given data represents the electrons in K, L, M, and N shells as 2, 8, 11, and 2.
Therefore, total number of electrons present in this neutral atom can be calculated as follows.
Total number of electrons = Electrons present in K + L + M + N shell
= 2 + 8 + 11 + 2
= 23
Thus, the no.of electron in a neutral atom of an element has 2K, 8L, 11M and 2N electrons is 23.
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