What is the normal reaction between A and B blocks if the system is in equilibrium? {g=10m/s2}
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Answer:
For equilibrium of 2kg−
T=2g where g=9.8m/s
2
And for equilibrium of 5kg−
⟹T+N=5g
⟹N=5g−T=3g
⟹N=3×9.8
⟹N=29.4N
Explanation:
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Given,
Mass of block A=1kg,
Mass of block B=2kg,
System is in equilibrium.
To Find,
The normal reaction between A and B blocks.
Solution,
For equilibrium of block B(2kg),
We know, T=2g where g=9.8m/s
Also for equilibrium of block A(1kg)
As we know, T+N=3g
⟹N=3g-2g
⟹N=g
⟹N=10N
Hence, the normal reaction between A and B blocks is 10 N.
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