what is the normality of 500ml NaoH contain 30g of NaoH
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1.5 M.
30g sample= 0.75 mole.
Explanation:
Gram formula mass of NaOH = 23g + 16g+ 1g = 40g
30g sample of NaOH = 0.75 mole
0.75mol/ 0.500L = 1.5 M
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