Question

What is the normality of 500ml solution of sodium hydroxide containing 30g NaOH?

Answer 1

Answer:

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Explanation:

1.5 M. 30g sample= 0.75 mole

Answer 2

1.5 N NaOH

Explanation:

Normality = gram equivalent per liter of solution.

NaOH has only 1 OH⁻, so the number of equivalent = 1

∴ Eq = 40/1 = 40

Number of moles = 30/40 = 0.75 moles

Normality = number of gram eq/V in L

                = 0.75/0.5 L

                = 1.5 N NaOH