Question

What is the normality of a 1.5 molar h2so4 solution?

Answer 1

Molarity of H2SO4 solution = 1.5 mol/L

n factor = 2

Normality of solution = M X n factor = 1.5 x 2 = 3

Answer 2

Answer:

The normality of $1.5M$ $H_{2}SO_{4}$ solution calculated is $3N$.

Explanation:

Data given,

The molarity of $H_{2}SO_{4}$ solution, M = $1.5M$

The normality of $1.5M$ $H_{2}SO_{4}$ solution, N =?

As we know,

• The relation between molarity and normality is given below:
• $Normality = n-factor\times Molarity$  -------equation (1)

Here,

• The n-factor is the number of electrons/hydrogen ions transferred.

Now, in $H_{2}SO_{4}$:

• $H_{2}SO_{4} \rightleftarrows 2H^{+} + SO_{4}^{2-}$

Here, $2$ hydrogen ions are transferred; therefore, n-factor = $2$

After putting the value of n-factor and molarity in equation (1), we get:

• Normality = $2\times 1.5$ = $3N$

Hence, the normality calculated is $3N$.