Question

What is the normality of NaOH have 500 mL required to neutralize a solution containing 1.5 gm of H2C2O4, At.wt for C=12, O=16, H=1 * 1 point 0.0070 gm.meq/L 0.070 gm.eq/L 0.0067 gm.meq/L 0.067 gm.eq/L The equivalent weight​

Answer 1

Example: How is a 1N solution of NaOH prepared?

Normality (N) = m /V × 1 / Eq

N = 1

m = unknown

V = 1 liter

Eq = 40.00g/eq (go back to the gram equivalent weight section if help is needed in remembering why this is so)

1 N = m /1L*× 1* / 40.00 g/eq

Using algebra and remembering that N is in eq/L:

m = 1 eq/L × 1 L × 40.00 g/eq ; therefore m = 40 g

To make a 1N solution of NaOH, 40 grams of NaOH are dissolved in 1 L.

Likewise, for a 0.1 N solution of NaOH, divide by a factor of 10 and 4 grams of NaOH per liter is needed.

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