Question

What is the normality of the salt obtained by mixing 100ml of 0.2M H2SO4 with 100ml of NaOH
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Answer 1

Since H2SO4 is dibasic there are 2 equivalents per mole. Therefore the solution has 0.05 x 2 = 0.1 equivalents per L which is 0.1 Normal. 0.4*100-0.2*100=N(resultant)*200(Here the sign changes to negative because NaOH and H2SO4 reacts to neutralize each other and hence there will be net decrease in Normality.

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Answer 2

Answer:

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Explanation:

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