Question

What is the nth term for 25,20,15,10,5
REALLY URGENT!!!!!!!!!!!

Answer 1

$tn = a + (n - 1)d \\ 25 + (n - 1)5 \\ 25 - 5 + 5n \\ 20 + 5n \\ 5(4 + n)$

Answer 2

Answer:

$n^{th} \: term (a_{n})=30-5n$

Step-by-step explanation:

$Given \: sequence \: 25,20,15,10,5$

$a_{2}-a_{1}= 20-25 = -5$

$a_{3}-a_{2}= 15-20= -5$

$a_{2}-a_{1}= a_{3}-a_{2}=-5$

$Therefore , common \: difference \\\:(d)=-5 , \: and\\ \: given \: sequence \: is \: in \: A.P$

$First \: term (a) = 25$

$we \: know \: that \\\boxed { n^{th} \: term = a_{n}=a+(n-1)d}$

$Now, here \\</p><p>a_{n}=25+(n-1)(-5)\\=25-5n+5\\=30-5n$

Therefore,

$n^{th} \: term (a_{n})=30-5n$

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