Math, asked by kotiankrithi215, 8 months ago

what is the nth term of an AP 17,12,7,2

Answers

Answered by TVerson2004
14

Answer:

22-5n

Step-by-step explanation:

An=a+(n-1)d

=17+(n-1)(-5)

=17-5n+5

=22+5n

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Answered by Anonymous
2

Given:

  • An A.P = 17,12,7,2

To Find:

  • The value of the nth term of the given AP.

Solution:

The general form of an AP is a+(n-1)d. In the given AP, a = 17, a+d = 12, a+2d = 7 and so on.

Let, t_n = a+(n-1)d → {equation 1}

First, we need to find the value of "d" since it should be substituted in equation 1.

Consider, a+d = 12

Substitute the value of "a = 17" in the above formula. We get,

d = 12-17  = -5

Substitute the obtained values in equation 1. We get,

t_n = 17+(n-1)(-5) = 17+(-5n+5)

In the above step, we solve for the values in the bracket first by multiplying and then adding them to get the value of the nth term.

t_n = 17 -5n + 5 = 22-5n

∴ The value of the nth term of the given AP = 22-5n.

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