Question

What is the nth term of this number sequence 15,12,9,6

Answer 1

The $n^{th}$ term of an AP is3(6 - n).

Step-by-step explanation:

The given sequence

15, 12, 9, 6

Here, first term(a) = 15, comon difference(d) = 12 - 15 = - 3

The given sequence are in AP.

∴ $n^{th}$ term of an AP

$a_{n} = a + (n - 1)d$

∴ $a_{n}$ = 15 + (n - 1)(- 3)

= 15 - 3n + 3

= 18 - 3n

= 3(6 - n)

Hence, the $n^{th}$ term of an AP is3(6 - n).