Question

what is the nth term of this sequence?
4, 6, 36, 64, 100

Answer 1

Finding the nth Term of an Arithmetic Sequence

Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d

Answer 2

Answer:

Here we are given with the numbers 4 16 36 64 100

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=12

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=20

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28100–64=36

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28100–64=36So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28100–64=36So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :100+44=144

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28100–64=36So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :100+44=144144+52=196

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28100–64=36So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :100+44=144144+52=196196+60=256

Here we are given with the numbers 4 16 36 64 100So in these kind of questions we have to find what common pattern is prevailing so in this one:Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:16–4=1236–16=2064–36=28100–64=36So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :100+44=144144+52=196196+60=256So the next 3 numbers are 144,196,256