Question

what is the number if photons of light with a wavelength of 4000pm that provides 1j of energy​

Answer 1

Answer:

What is the number of photons of light with a wavelength of 4000 pm that provide 1J of energy? ∴ N = E×λ/h×c = (1J×4×10-9 m)/(6.626×10-34 Js×3.0×108 ms-1) = 2.012×1016 photons.

Explanation:

please mark me down as a brain liest

Answer 2

Given and to find:

→ What is the number if photons of light with a wavelength of 4000 pm that provides 1j of energy.

‎‎‎‎‎‎‎‎ㅤ

Using formula:

★ E = he/λ

‎‎‎‎‎‎‎‎ㅤ

We know that:

→ $\sf{c = 3 \times 10^{8} m/s}$

‎‎‎‎‎‎‎‎ㅤ

Calculations:

→ $\sf{λ = 4000 \times 10^{2} m = 4 \times 10^{-8}m}$

‎‎‎‎‎‎‎‎ㅤ

→ $\sf{E = \dfrac{(6.626\times 10^{-34}Js) \times (3 \times 10^{8}ms^{-1})}{(4\times 10^{-9}m)}}$

‎‎‎‎‎‎‎‎ㅤ

→ $\sf{4.969 \times 10^{-17}J}$

‎‎‎‎‎‎‎‎ㅤ

Dividing by 1J energy of photons, we get;

→ $\sf{2.012 \times 10^{16} \: photons}$