Question

What is the number of atom in 1.4g of nitrogen gas?

Answer 1

answer is 6.022*10 (22)

Answer 2

Answer:

6.022×10²²

Explanation:

no. of atoms = (weight/atomic Wt.) × Avogadro's No

                     = (1.4/28) × 6.022 × 10²³

                     = (1/20) × 6.022 × 10²³

                     = 3.011 × 10²²

Since Nitrogen has 2 molecules

= 3.011 × 10²² × 2

= 6.022×10²²