What is the number of atoms in 96g of O2?
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Explanation:
Molar mass of O2=32g=M
Given Mass of O2=96g=m
No.of particles=X
Avogadro's Number=6.022x10^23=N(a)
According to Question
m/M=X/N(a)
96/32=X/6.022x10^23
3=X/6.022x10^23
X=3x6.022x10^23
X=18.066x10^23 atoms
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