Question

What is the number of atoms of oxygen in 3.42 grams of cane sugar?

Answer 1

Given ;

• W = 3.42g

Cane sugar = C12H22O11

• M = 342 g/mol.

Therefore moles of cane sugar

• n = W/M
• n = 3.42 / 342
• n = 1/100 moles.

In 1 molecule ; 11 atoms of O

Thus in 1/100 moles ; 11/100 moles of O

Thus number of O atoms ; N

• N = n × NA. {NA = Avagadro's number}
• N = 11/100 × 6.022 × 10²³
• N = 66.242 × 10²¹ atoms of O

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