Biology, asked by noorulayn, 1 year ago

what is the number of dominant alleles in a population of 100 individuals with the following genotype:30BB,60Bb,10bb

Answers

Answered by Anonymous
5
dominant alleles is B
90 out of100 will be of B.

noorulayn: i still didnt get the answer..
noorulayn: is there any formula? the answer is 60 dominant alleles
Anonymous: it should be 90
Anonymous: sorry
noorulayn: how?
shivam8899: according to Hardy-Weinberg QOD
Anonymous: can u explain????
shivam8899: according to Hardy-Weinberg QOD, Individuals: p^2 + 2pq + q^2 = 1...but for frequency ....so BB is dominant genotype....so first we find frequency ..then 30/100 = 0.3 and p^2 = 0.3 so p = 0.55 so and no. of dominant alleles is total no. of individuals x frequency of dominant allele so we get 0.55 x 100 = 55 near about 60 ...and we select 60 according to option of this question /......i hgope it will help you ..regard
Answered by shivam8899
2
according to Hardy-Weinberg QOD,
Individuals: p^2 + 2pq + q^2 = 1
but for frequency
so BB is dominant genotype....
so first we find frequency .
.then 30/100 = 0.3 and p^2 = 0.3
so p = 0.55 so
and no. of dominant alleles=total no. of individuals x frequency of dominant allele
so we get
0.55 x 100 = 55 near about 60
and we select 60 according to option of this question
i hope it will help you
regard

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