What is the number of edges of a pyramid, if the number of faces and vertices are 4 and 4 respectively ?
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Answered by
16
Answer :-
Euler's polyhedron formula, V−E+F=2
V = number of vertices = 4
V = number of vertices = 4E = number of edges =?
V = number of vertices = 4E = number of edges =?F = number of faces = 4
Thus 4−E+4=2
⇒E=8−2
⇒E=6
Number of edges = 6
Hope it will help you :)
Answered by
4
Step-by-step explanation:
the answer will be 6
v-e+f = 2
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