Question

what is the number of esters of c5h10o2

Answer 1

↪↪↪↪HERE IS UR ANSWER⤵⤵⤵⤵

You know that the ester group is 

COO 

The general formula for the ester is 

R1COOR2 

You also know that you have C4H10 to play with 

So if R1 = H 

R2 = C4H7 

There are 4 structural isomers of C4 H7 

They are n-butyl CH3CH2CH2CH2- 

isobutyl or 3methylpropyl 

(CH3)2CHCH2 

sec-butyl or 2methylpropyl 

CH3CH(CH3)CH2- 

(by the way, this one is chiral so it really is 2 isomers) 

t-butyl or 1,1-methylethyl 

(CH3)3C- 



If R1 = CH3 Then R2 = C3H7 

There are 2 isomers of C3H7 

n-propyl CH3CH2CH2 

iso-propyl or 1methylethyl (CH3)2CH- 

If R1 = CH3CH2 then R2 = CH3CH2- there is only one isomer 

If R1 = C3H7 then R2 = CH3 As mentioned above, there are 2 isomers of C3H7 

If R1 = C4H9 then R2 = H. That's not an ester. If R2 = H, it's a carboxylic acid. 

So of the formate ester, 4 structural isomers one of which is chiral and has two stereoisomers for a total of 5 isomers 

of the acetate ester, 2 structural isomers 

of the propionate ester, 1 structural isomer 

of the butrate ester, 2 structural isomers 

no pentanoate esters 

A total of 9 structural isomers one of which is chiral for a total of 10 isomers. 

There may be some systematic way to do this but for a relatively simple compound like this, I don't know it. I don't know if I would say many trial and error. You do this kind of thing once and you pretty much know how to do it. 


HOPE IT HELPS YOU

Answer 2

Explanation:

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