What is the number of gram atoms present in 10 grams of caco3?
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Answered by
27
here, given weight = 10g
molecular weight of CaCO3 = 100g/mol
mole = 10g/100g/mol = 0.1 mole
hence, 0.1 g atom
Answered by
4
Answer:
0.1g
Step-by-step explanation:weight 10g , caco3=40+12+3×16=40+12+48=100g atwt/gmwt=10/100=0.1g
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