Question

What is the number of H+ ions in 9.8 g of H3PO4?

Answer 1

Explanation:

The molar mass of H2SO4 is 98.1

so 9.8 g would equate to 0.0999 mols of H2SO4

We can then multiply 0.0999 mols by Avogadro’s number (6.02 x 10^23) to find that there are roughly 6.02 x 10^22 molecules of H2SO4 in 9.8g of the compound.

But, because H2SO4 is a diprotic acid, therefore we need to multiply the quantity of H2SO4 molecules in 9.8g by 2.

Hence, in 9.8g of H2SO4, there are roughly 1.2 x 10^23 H+ ions.