what is the number of hydrogen bonds in a dna of 1000 base pairs with base a occurring 75% of times in 1 stand and 10% in other stands
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Answer: hey mate!!!!
Total adenine + thymine in both the strands become 85% .
So the sum of guanine and cytosine will be (100–85)%=15%
As the total no. of bases are 1000.
No. of adenine + thymine will be 85% of 1000= 850 bases. And no. of cytosine+ guanine will be 15% of 1000= 150 bases.
Adenine joins by forming two H bonds with thymine. Therefore, 850 bases will join by 850*2 bonds = 1700 H bonds.
Guanine joins to cytosine by forms 3 H bonds. Therefore, 150 bases will form 150*3 bonds = 450 bonds.
total no. of H bonds formed in B-DNA of 1000 bp length is 1700+450 = 2150 H bonds.
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