Question

What is the number of moles of ammonia gas is formed when 0.5 moles of nitrogen gas is reached with excess of hydrogen gas?

Answer 1

Answer:

So if each coefficient is multiplied by a mole, the balanced chemical equation tells us that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia

Answer 2

Answer:

1 mole of ammonia gas is produced.

Explanation:

• The general equation of formation of ammonia is written below.

        $N_{2} (g) + 3H_{2} (g)$ → $2NH_{3} (g)$

• One mole of nitrogen molecules reacts with three moles of hydrogen molecules to produce two moles of ammonia.
• In this question, the moles of nitrogen are limited; hence, nitrogen is the limiting reagent.
• 0.5 moles of nitrogen molecules react with excess hydrogen molecules to produce a certain amount of ammonia.

                  $N_{2}$             $NH_{3}$

Moles:        1                2

                  0.5            $x$

2 × 0.5 = 1 × $x$

1 = 1$x$

$x$ = 1                  

Conclusion:

Only 1 mole of ammonia is produced when 0.5  nitrogen gas reacts.