Question

What is the number of moles of electrons transferred when 3 moles of pb(n3)2 is oxidised?

Answer 1

the complete equation is Pb(N3)2 + Cr2O3 yeilds Cr2O3 + MnO2 + Pb3O4 + NO. We were told to assume the equations were being carried out in an acid soultion and to use the half-reduction method to balance the equation. I have four half-reaction equations. Mn7+ + 3e- yeilds Mn4+, Cr2+ yeilds Cr6+ + 4e-, N(3 as a subscript)- yeilds 3N+ + 3e-, and

3Pb2+ yeilds 3Pb(8/3)+ +2e-.

This can't be because there are three elements undgoing oxidation and only one undergoing redox.

Answer 2

11.2 lit contains 0.5 moles of oxygen. .

no. of oxygen molecule= 6.022×10²³×0.5

no of oxygen atom=2×0.5×6.922×10²³( because each oxygen molecule has 2ocygen atoms)

= 6.022×10²³

Hope this helps ☺️☺️