Question

What is the number of particles of 35.20 g sulfuric acid

Answer 1

Number of particles of 35.20 g sulfuric acid is 1.806×10²³

Molarity is the number of moles of solute per litre of soltion.

Explanation:

Molecular weight of Sulfuric acid is 98 gm

Given weight is 35.20gm

Normality= Number of gram equivalents in solute÷ volume of solvents in liter

Number of moles= Given weight ÷Molecular weight

=35.20÷98

=0.359

0.3 moles of Sulphuric acid is 35.20 gm

Number of molecules in 0.3 moles of sulphuric acid=0.3 ×6.023 ×10²³

= 1.806×10²³

Answer 2

• The molar mass of sulphuric acid is 98.

        The molar mass is the mass of 6.022 × 10²³ particles.

Let 'x' be the number of particles having a  mass of 35.2g

Mass of 6.022 × 10²³ particles = 98 g

∴Mass of x paritcles = 35.2 g

X = 6.022 × 10²³ × 35.2/98

  = 2.16 × 10²³  

35.2 g of sulphuric acid will have 2.16 × 10²³  particles.