Question

What is the number of photon of light with a wavelength of 4000 pm that provide 1joule of energy?

Answer 1

Answer:

2×10^14

Explanation:

E =nhv

where n= no of photons,

h= plank's constant

1= n × 6.63 × 10^-34 × c/ wave length

n= 4000 × 10 ^-12/6.63×10 ^-34× 3×10^8

n=2 × 10 ^ 14