Question

what is the number of photon the light with wavelength 400pm that provide 1j of energy ( h= 6.6*10​

Answer 1

Answer is :- 2.01×10

18

J.

Explanation:

HINT:- Energy of light is inversely proportional to the wavelength.

Formula :- The energy one photon =

hc

λ

Here, c is velocity of light , λ is wavelength and h is plank's constant.

Step:1 To find the energy of one photon.

Step:1 To find the energy of one photon.Given that,

Step:1 To find the energy of one photon.Given that,The wavelength of light =4000pm or 4000×10

Step:1 To find the energy of one photon.Given that,The wavelength of light =4000pm or 4000×10 −12

Step:1 To find the energy of one photon.Given that,The wavelength of light =4000pm or 4000×10 −12 m or 4×10

Step:1 To find the energy of one photon.Given that,The wavelength of light =4000pm or 4000×10 −12 m or 4×10 −9

Step:1 To find the energy of one photon.Given that,The wavelength of light =4000pm or 4000×10 −12 m or 4×10 −9 m.

The energy one photon =

The energy one photon = λ

The energy one photon = λhc

The energy one photon = λhc

The energy one photon = λhc =

The energy one photon = λhc = 4×10

The energy one photon = λhc = 4×10 −9

The energy one photon = λhc = 4×10 −9

The energy one photon = λhc = 4×10 −9 6.626×10

The energy one photon = λhc = 4×10 −9 6.626×10 −34

The energy one photon = λhc = 4×10 −9 6.626×10 −34 ×3×10

The energy one photon = λhc = 4×10 −9 6.626×10 −34 ×3×10 8

The energy one photon = λhc = 4×10 −9 6.626×10 −34 ×3×10 8

The energy one photon = λhc = 4×10 −9 6.626×10 −34 ×3×10 8

The energy one photon = λhc = 4×10 −9 6.626×10 −34 ×3×10 8 =4.97×

10

10 −17

10 −17 .

10 −17 .Step:2 To find the number of photons that provide 1J of energy.

The number of photons that will provide 1 J of energy is

The number of photons that will provide 1 J of energy is 4.97×10

The number of photons that will provide 1 J of energy is 4.97×10 −17

The number of photons that will provide 1 J of energy is 4.97×10 −17

The number of photons that will provide 1 J of energy is 4.97×10 −17 1

The number of photons that will provide 1 J of energy is 4.97×10 −17 1

The number of photons that will provide 1 J of energy is 4.97×10 −17 1 J=2.01×10

The number of photons that will provide 1 J of energy is 4.97×10 −17 1 J=2.01×10 18

The number of photons that will provide 1 J of energy is 4.97×10 −17 1 J=2.01×10 18 J.

The number of photons that will provide 1 J of energy is 4.97×10 −17 1 J=2.01×10 18 J.Final answer: 2.01×10

The number of photons that will provide 1 J of energy is 4.97×10 −17 1 J=2.01×10 18 J.Final answer: 2.01×10 18

The number of photons that will provide 1 J of energy is 4.97×10 −17 1 J=2.01×10 18 J.Final answer: 2.01×10 18 J.