What is the number of photons of light with a wavelength of 4000
pm that provide 1j of energy?
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Answered by
25
Energy of photon = hc/lembda
→ where lembda = wavelength of light = 4000*10^-12m
→ C = velocity of light =3*10^8m/s
h = planks constant =6.626×10^-16
therefore,
E = 6.626*10^-34×3*10^8/ 4000*10^-12
E =4.96×10^-19
now,
4.96 ×10^-16 J is the energy of one photon
so,
1J will be the energy of 1/4.96*10^-16
=2×10^15photons
:)
Answered by
8
Answer:
2×10^16 photons.
Explanation:
See the picture.
Hope it helps.
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