Question

What is the number of photons of light with a wavelength of 4000pm that provides 1j of energy?

Answer 1

Answer:

2.014×10^16photons.

Explanation:

from the formula,

E=n×h×c/wavelength

1=n×6.62×10^-34×3×10^8/4000×10^-12

1=n×9.93×10^-17/2

n=2/9.93×10^-17

n= 2.04×10^16photons. Ans

Answer 2

Answer:

Explanation

Wave length=4000pm

From the formula below

E =n.h.c/ length

N*6.626*10^-34*3*10^-8/4000*10^-12

(2/9.93)*10^16

2.04*10^16 photons