Chemistry, asked by mahekCalcuttawala, 6 months ago

what is the number of revolution of an electron in Bohr orbit of H atom in one second
(a) 8.2*10^14(b) 16.4*10^14
(c) 4.1*10^14 (d) 4.1*10^14​

Answers

Answered by pawanbhavanam2
0

Answer:

Explanation:

If r2 is the radius of second bohr orbit, the distance travelled by an electron is

2 pi r2

Number of revolutions per second=V2/2 pi r2

r2=2^2(r1)

4*0.53*10^-8=2.12*10*^-8 cm

number of revolutions=1.09*10^8/2*3.14*2.12*10^-8

8.18*10^14

8.2*10*^14

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