Question

what is the number of revolutions of electron in second Bohr's orbit of H atom in one second

Answer 1

Frequency = 1Time period1Time period

Time period = Total distance coveredVelocity=2πrvTotal distance coveredVelocity=2πrv

Frequency = v2πrv2πr

The velocity (v2)(v2) and radius (r2)(r2) of the 2nd2nd Bohr's orbit :

rn=(0.53×10−10n2/z)mrn=(0.53×10−10n2/z)m

r2=(0.53×10−10(22)m=2.12×10−100mr2=(0.53×10−10(22)m=2.12×10−100m

vn=2.165×106(z/n)m/svn=2.165×106(z/n)m/s

v2=2.165×106(1/2)=1.082×106m/sv2=2.165×106(1/2)=1.082×106m/s

Frequency=v22πr2=1.082×1062(π)(2.12×10−10)v22πr2=1.082×1062(π)(2.12×10−10)

v=8.13×1016Hz