What is the number of solutions of the pair of linear equation 4p-6q+18 = 0 and 2p-3q +9 = 0?
Answers
Answer:
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Given : pair of linear equation 4p-6q+18 = 0 and 2p-3q +9 = 0
To Find : number of solutions
Solution:
Pair of linear equations
a₁x + b₁y + c₁ = 0
a₂x + b₂y + c₂ = 0
Consistent
if a₁/a₂ ≠ b₁/b₂ (unique solution and lines intersects each others)
a₁/a₂ = b₁/b₂ = c₁/c₂ (infinite solutions and line coincide each other )
Inconsistent
if a₁/a₂ = b₁/b₂ ≠ c₁/c₂ ( No solution , lines are parallel to each other)
4p-6q+18 = 0
2p-3q +9 = 0
4/2 = - 6/-3 = 18/9
=> 2 = 2 = 2
Hence infinite solutions and line coincide each other
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