Question

What is the number of terms in the series 117, 120, 123, 126,.............., 333?

Answer 1

Here is ur answer !!!

a = 117

d = 3

n = ?

An = a + (n-1)d

333 = 117 + 3n - 3

333-114 = 3n

n = 219/3

n = 73


Hope it helps u :-)

Answer 2

Hey !!


AP = 117 , 120 , 123 , ......... , 333


Here,

First term ( a ) = 117


Common difference ( d ) = 3


Last term ( Tn ) = 333



a + ( n - 1 ) × d = 333


117 + ( n -1 ) × 3 = 333


117 + 3n - 3 = 333

3n + 114 = 333


3n = 333 - 114


3n = 219


n = 73.


Hence,

Number of terms = 73.