Question

what is the number of water molecules contained in a drop of water weighing 0.006 gram​

Answer 1

Answer:

1 mole of water = 6.022 x 1023 molecules of water

Gram molecular mass of water = 2 + 16 = 18 grams

i.e. 18 g of water contains = 6.022 x 1023 molecules

begin mathsize 14px style space space So comma space 0.06 space straight g space water space contains space equals fraction numerator 6.022 cross times 10 to the power of 23 cross times 0.06 over denominator 18 end fraction space end style

                                  = 2.007 x 1021 molecules

Explanation:

Answer 2

Answer:

2.008×10^20 molecules

Explanation:

18gm H2O contains 6.023x10^23 molecules

1gm contains (6.023×10^23)/18=3.347×10^22 molecules

.006gm contains 3.347×10^22×0.006= 2.008×10^20 molecules