What is the number of water molecules contained in a drop of water weighing 0.06g?
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Answer:
given wt. = 0.06g
molecular wt. = 18g
number of moles = 0.06/18 = 0.0033
so, required number of water molecules
= 0.0033 × 6.022 × 10²³
= 0.0198 × 10²³
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