Question

What is the number of zeros at the end of the product 5^5x 10^10× 15^15 x ......... x 125^125​

Answer 1

Answer:

880

Step-by-step explanation:

10^10^20^20^30^30^___ ^90^90

each will have 10,20,30 ,___,90zeroes at the end respectively,(450zeroes)

100^100will have 200 zeroes at the end,110^110&120^120will have 110&120 zeroes at the end resp.

=5^5,15^15,25^25,___125^125

will not have any zeros

there is no number that end with 2,4,6,8 to contribute zers in multiplication with number ending with 5.

total zeros at the end are

=450+110+120+200=880

I think it helps u..

plz.. mark it as brainlist answer

Answer 2

Answer:

1520

Step-by-step explanation:

As we know to solve this type of problems we need to count number of 5s or 2s (it depends on least number of occurrence in the given problem)

Here we have to count the number of 2 rather than just counting zeros in 10 digit numbers like 10 20 30 and so on.

like if we see in number 20 we have 20 zeros coming from the power as other are saying but also there are more 20 2s remaining that will lead to another 20 number of 10

so all the above methods that are chosen to solve this problem is totally wrong…

here we have to count the number of 2s as i have said earlier

now this part might get a little bit hard so stay with me!!

we have to count number multiples of 2^1,2^2,2^3,2^4… so on until we don’t get any multiple left….

number of multiples of 2=10+20+30+….120=780

number of multiples of 2^2=20+40+60+80+100+120=420

number of multiples of 2^3=40+80+120=240

number of multiples of 2^4=80

number of multiples of 2^5=0 , we stop here….

now adding them we get 1520 that’s the answer!!