Chemistry, asked by anjanaas, 1 year ago

What is the number of zinc atoms in a piece of zinc weighing 10g

Answers

Answered by coolbob2002
18
6.023×10 to the power of 21 × 10 g is ans

aiswaryaanithrk: Number of atoms = (Mass/Molar mass of Zn)* Avogadro number

=(10/65)*6.023*10^23

=9.26*10^23

Therefore,9.26*10^23 particles are present in 10 g of zinc
Answered by Anonymous
18
Since it's given that the molar mass of zinc is 65 gram i.e 65gram of zinc constitutes 6.022 x 10^23 atoms or 1 mole of atoms so by unitary method, 1 gram of zinc would have 1/65 moles of zinc and similarly 10 gram of zinc would have 10/65 moles of zinc which is equal to 10 x 6.022 x 10^23 / 65 atoms which is 
Similar questions