Math, asked by emphasisbadamba, 3 months ago

What is the numbere which when divided
by 8,12, and 15 leaves a remainder 3 in
each case?​

Answers

Answered by avaniarora49ambala
0

Answer: 123

Step-by-step explanation:

To find the number, you need to follow the following steps -

Find out the LCM (lowest common multiple) of the three numbers - 8, 12 and 15, which, in this case will be 120.

Then add 3 to it, thus making it 123. This is the least number which when divided by 8, 12 or 15 has a remainder of 3 in each case.

To find more such numbers, find multiples of LCM (i.e., 120) and add 3. Like, 123 (120 * 1 + 3), 243 (120 * 2 + 3), 363 (120 * 3 + 3) and so on.

Summarising, the general formula for such a question would be -

((LCM (n1, n2, n3)) * N) + 3

where,

n1, n2, n3 - the three numbers.

N - natural number (1, 2, 3, and so on)

Hope I helped!

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Answered by archanakumari90980
0

get the best answer follow the steps are as follows:

First you have to find out the L. C. M. ( lowest common multiple) of the number 8,12 and 15 .

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