Question

What is the numerator of equivalent fractions of 5/7 with denominator 49

Answer 1

$let \: the \: number \: be \: x \\ it \: is \: given \: that \: they \: are \: equivalent \\ \: so \: \: \: \: \: \: \: \: \: \: \: \frac{5}{7} = \frac{x}{49} \\ by \: cross \: multiplication \\ 7x = 49 \times 5 \\ x = \frac{49 \times 5}{7} \\ x = 7 \times 5 \\ x = 35 \\ \\ by \: unitary \: method \\ \frac{5}{7} = \frac{x}{49} \\ 49 \: is \: seven \: times \: the \: 7 \\ and \: both \: are \: dinominators \\ so \: we \: will \: multiply \: by \: 7 \: to \: 5 \: to \\ get \: the \: value \: of \: x \\ \frac{5 \times 7}{7 \times 7} \\ = \frac{35}{49} \\ hence \: the \: value \: of \: x \: is \: 35 \\ in \: both \: the \: cases$