Question

what is the numerical aperture of on optical fiber cable with a cladding
index of 1.378 and a core index of 1.546.​

Answer 1

Answer:

alway written as given

Answer 2

Given info : core refractive index is 1.546 and that of cladding is 1.378

we have to find the numerical aperture and acceptance.

solution : Numerical aperture is a dimensionless quantity that characterizes the range of angles over the system can emit or accept of light. in short, it is a measure how much light can be collected by an optical fibre system.

it is determined by the relative magnitude of refractive index in the core and in the cladding.

formula of numerical aperture is given by, NA = √(n₁² - n₂²) , where n₁ is refractive index in the core and n₂ refractive index in the cladding.

here n₁ = 1.546 and n₂ = 1.378

so, NA = √(1.546² - 1.378²) = 0.700879 ≈ 0.7

Therefore the numerical aperture of on optical fiber cable is 0.7