Question

What is the % of free SO3 gas in the sample of oleum labelled as 103%?

Answer 1

Explanation:

103% Sample of Oleum means in 100 gm oleum (i.e. SO 3 + H 2 SO 4 ) 9 gm H 2 O is added to convert the free SO 3 gas to H 2 SO 4 .

80 gm SO 3 reacts with 18 gm H 2 O to form H 2 SO 4 .

Thus, 9 gm H 2 O reacts with 40 gm SO 3 to form H 2 SO 4 .

So, percentage of free SO 3 in the sample will be 40.

Answer 2

Explanation

oleum Labelling= 100% + % water

103% = 100% +%water

% water = 3%

3% Water in 100 gm solution means it weighs 3gm

3/100×100 = 3gm

Complete Answer Is in attachment