Chemistry, asked by Arnnabh, 9 months ago

What is the % of NaCl in mixture if 250 ml of solution of NaCl and Na2CO3 was prepared by dissolving 4gm of their mixture in H2O. 25ml of this solution was completely neutralised by using 50 ml of N/10 HCl.

Answers

Answered by hcps00
1

Explanation:

ANSWER

Weight of Na

2

CO

3

=ag

Weight of NaCl=bg

a+b=H

Only Na

2

CO

3

reacts

In 15 ml, M eq of Na

2

CO

3

= M eq of HCl

→50∗

10

1

=5

M eq of Na

2

CO

3

in 250ml = \frac {5 * 250} {25}$$

→50

Answered by madhunisha05
1

Answer:

ANSWER

Weight of Na

2 CO3

=ag

Weight of NaCl=bg

a+b=H

Only Na 2 CO 3

reacts

In 15 ml, M eq of Na2co3

= M eq of HCl

→50∗

10

1

=5

M eq of Na

2 Co3

in 250ml = \frac {5 * 250} {25}$$

→50

Explanation:

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