Question

What is the % of water in FeSO4. 2H20​

Answer 1

Given the Compound = Fe2SO4 . 2H2O

Molecular Mass of Fe = 56 g, S = 32 g, O = 16 g, H = 1 g,

Molar Mass of Fe2SO4.2H2O = (56*2)+32+(16*4)+(18*2) g

= 228 g

Percentage Composition of H2O in the compound is = (36/228)*100 %

= 15.78%

I hope this helps.