What is the oh- concentration in a solution with a ph of 4.51?
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ph = 4.51
poh + ph = 14
poh = 14-4.51= 9.49
by taking antilog
concentration of oh- will be
approximately 4 × 10^-10
ph = 4.51
poh + ph = 14
poh = 14-4.51= 9.49
by taking antilog
concentration of oh- will be
approximately 4 × 10^-10
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