Question

What is the [OH-] in the final solution prepared by
mixing 20.0 mL of 0.050 M HCl with 30.0 mL of
0.10 M Ba(OH),?
​

Answer 1

Answer:

Hmm hai

Explanation:

20 words 20 words

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Answer 2

Explanation:

Millimoles of H+ produced = 20 x 0.05 = 1 Millimoles of OH- produced = 30 x 0.1 x 2 = 6

(... Each Ba(OH)2 gives 2OH-.) .

.. Millimoles of OH- remaining in solution = 6 - 1 = 5

Total volume of solution = 20 + 30 = 50 mL . .. [OH-] = 5/50 = 0.1

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