Question

What is the osmotic pressure of 0.2 m hx(aq.) solution at 300 k? (given: ka(hx)=8105)

Answer 1

What is the osmotic pressure of 0.2 m hx(aq.) solution at 300 k? (given: ka(hx)=8105). Answer.

Answer 2

Answer:

4.926 atm

Explanation:

Here, HX => (H^+) + (X^-)

Then the Rate of reaction = Ka * [HX]

Here that rate is also α

So α = 8*10^-5*0.2 = 1.6*10^-5

Hence n = 2 so i = 1+α = 1(approximate)

Finally π = icrt = 1*0.2*0.0821*300 = 4.926 atm