Question

what is the output ? int main(){ int x = 10; { int x = 0; printf("%d",x); } return 0;} *


(A) 10

(B) Compilation Error

(C) 0

(D) Undefined​

Answer 1

Answer:

(B),

Explanation:

it looks like a mixture of python and c++

Answer 2

Answer:

The output of the given code is (C) 0

Explanation:

• The program consists of only the main function.
• A local variable x of integer data type is initialized to 10 at the beginning of the program.
• After the initialization, a block of statements is enclosed within curly brackets.
• Inside these curly brackets, the value of variable x is reinitialized to zero and is then printed.
• Enclosing the block of statements in separate curly brackets ensures that the value of the variable x which is local to that block is printed.
• Once the printf statement is executed, the value of variable x which is local to the main function is restored to 10.
• Since there is no printf statement after the inner block, this value of variable x which is local to the main function is not being printed and the program is terminated.

Therefore, on successful execution of this program, the output printed will be 0.

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